If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0.2x^2+2.2x+1.5=0
a = 0.2; b = 2.2; c = +1.5;
Δ = b2-4ac
Δ = 2.22-4·0.2·1.5
Δ = 3.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{3.64}}{2*0.2}=\frac{-2.2-\sqrt{3.64}}{0.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{3.64}}{2*0.2}=\frac{-2.2+\sqrt{3.64}}{0.4} $
| -10u−10=10−6u | | d+2d=d= | | 6+9s=8s | | -3-7g=-4g | | 2(1/2+3c/2)-3c=1 | | d=2d+4 | | 2=x4−7 | | 2=x4−7; | | R(x)=x2+2 | | -63=f.9 | | 11x+4+6x-9=16x+2 | | Q(x)=-3x+10 | | 4(2k-5)=12 | | x-22=65 | | (5^2x4)/(3^3-2)=x | | 6x9=2x+7 | | 6x-9=2x=+7 | | 1/2a+6=2a | | m/2+1=7/4 | | 7m+3=34 | | 2g+6=-20 | | 2((1+3c)/2)=0 | | 2(1+3c/2)=0 | | 57x-1+56=112x | | -2x+5+11x=x+3 | | 2x+9=9x+4 | | -2x+5+11x=1x+3 | | -2x+5+11x=33x+3 | | 4(x-3)=3x+17 | | 2(1+3c/2)-3c=1 | | -2x+5+11x=2x+3 | | 6x-9=2x+.7 |